5p^2-32p+35=0

Solution for 5p^2-32p+35=0 equation:

5p^2-32p+35=0

a = 5; b = -32; c = +35;
Δ = b2-4ac
Δ = -322-4·5·35
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-18}{2*5}=\frac{14}{10}
=1+2/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+18}{2*5}=\frac{50}{10}
=5
$